Suppose f : X→Y is a quotient map between spaces such that it maps a subset A→X injectively into Y and maps X\A onto Y\p(A). Then Y is homeomorphic to the adjuction space X∪p|X\A(Y\p(A)).
pf> Let A'=X\A, B=p(A), B'=Y\p(A). Let π:X∪B'→X∪p|A'B' be the quotient map defining the adjunction space, and let φ:X∪p|A'B'→Y be a map defined in the obvious way. Then clearly φ is bijective. I'll show it's homeomorphism.
Suppose U⊆Y is open. π-1φ-1(U)=p-1(U) so is open in X, and π-1φ-1(U)∩B' =U∩B' is obviously open in B' so π-1φ-1(U) is open in X∪B', and hence φ-1(U) is open in X∪p|A'B'.
Now suppose V⊆Y is a subset such that φ-1(V) is open. Then π-1φ-1(V) is open. Since p-1(V)=π-1φ-1(V), V is open in Y. QED
Thursday, October 16, 2008
Saturday, October 4, 2008
Primes and primaries in module
M an R-module.
An element r∈R is a zero divisor in M if rm = 0 for some m≠0. r is a zero in M if rm = 0 ∀m∈M. r is a nilpotent in M if some positive power of r is a zero in M. Provided M≠0, zeros ⊆ nilpotents ⊆ zero divisors.
Let N⊆M be a submodule. N is a prime submodule if N≠M and every zero divisor in M/N is a zero in M/N. N is a primary submodule if N≠M and every nilpotent in M/N is a zero divisor in M/N. Then prime submodules are primary.
Let P⊆M be a prime submodule. Then (P:M) is a prime ideal.
Let Q⊆M be a primary submodule. Then (Q:M) is a primary ideal.
If one defines rad(N)=rad((N:M)) for submodules N⊆M, then rad(Q)=rad((Q:M)).
An element r∈R is a zero divisor in M if rm = 0 for some m≠0. r is a zero in M if rm = 0 ∀m∈M. r is a nilpotent in M if some positive power of r is a zero in M. Provided M≠0, zeros ⊆ nilpotents ⊆ zero divisors.
Let N⊆M be a submodule. N is a prime submodule if N≠M and every zero divisor in M/N is a zero in M/N. N is a primary submodule if N≠M and every nilpotent in M/N is a zero divisor in M/N. Then prime submodules are primary.
Let P⊆M be a prime submodule. Then (P:M) is a prime ideal.
Let Q⊆M be a primary submodule. Then (Q:M) is a primary ideal.
If one defines rad(N)=rad((N:M)) for submodules N⊆M, then rad(Q)=rad((Q:M)).
Thursday, October 2, 2008
Continous map from topological sum
Let {Xα}α, Y be disjoint spaces, and fα:Xα→Y continuous maps. Then the natural induced map from the topological sum ∪αXα to Y is continuous.
Adjunction space and quotient topology
Let X and Y be disjoint spaces, and A⊆X a subset.
Let f: A→Y be a function. Let Z=(X-A)∪Y be the disjoint union of sets. Then there is a natural surjection from X∪Y(as topological sum) to Z. The quotient topology on Z induced by this function is none other than the adjuction space X∪fY.
Let f: A→Y be a function. Let Z=(X-A)∪Y be the disjoint union of sets. Then there is a natural surjection from X∪Y(as topological sum) to Z. The quotient topology on Z induced by this function is none other than the adjuction space X∪fY.
Adjunction space
Suppose a function between spaces f: X→Y.
The adjuction space X∪fY is homeomorphic to Y if and only if f is continuous.
The adjuction space X∪fY is homeomorphic to Y if and only if f is continuous.
Wednesday, October 1, 2008
Coherent topology
Suppose X is a space coherent with a family of its subspaces {Xα}α.
Then a map f: X →Y is continuous if and only if f|Xα:Xα→Y is continuous for every α.
Then a map f: X →Y is continuous if and only if f|Xα:Xα→Y is continuous for every α.
Topological sum(Munkres)
X a space, {Uα}α a family of disjoint open sets of X. X is a topological sum of Uα's if X is a disjoint union of them.
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